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  Compare Table value!!  shekarls at 05:35 on Tuesday, November 21, 2006
 

For table "User"
ID NAME AGE
1 Rick 28
2 Raj 30
3 Lucku 35

if(_condition(_getCellText(_cell(_table("User"), 1, 4)) == "30"))
_alert("Age is correct");
else
_alert("Wrong Age!");

HI all,
Is my code correct??.
I tried using this Code, to verify whether Name "Ricky" is equal to the age 30, using my code it should fail saying "Wrong Age", as Ricky's age is 28.
Can anybody guide me about this!!

Thanks in Advance
shekar :)









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